Question

[Nguyễn Quốc Đạt]

Tính rồi rút gọn (theo mẫu):

Mẫu: \(\dfrac{5}{6}+\dfrac{4}{6}=\dfrac{5+4}{6}=\dfrac{9}{6}=\dfrac{3}{2}\)

a) \(\dfrac{1}{8}+\dfrac{5}{8}\)                         b) \(\dfrac{1}{15}+\dfrac{4}{15}\)                     c) \(\dfrac{5}{9}+\dfrac{7}{9}\)                         d) \(\dfrac{23}{100}+\dfrac{27}{100}\)

Answer 1

[Nguyễn Lê Phước Thịnh]

a: \(\dfrac{1}{8}+\dfrac{5}{8}=\dfrac{1+5}{8}=\dfrac{6}{8}=\dfrac{3}{4}\)

b: \(\dfrac{1}{15}+\dfrac{4}{15}=\dfrac{1+4}{15}=\dfrac{5}{15}=\dfrac{1}{3}\)

c: \(\dfrac{5}{9}+\dfrac{7}{9}=\dfrac{5+7}{9}=\dfrac{12}{9}=\dfrac{4}{3}\)

d: \(\dfrac{23}{100}+\dfrac{27}{100}=\dfrac{23+27}{100}=\dfrac{50}{100}=\dfrac{1}{2}\)

Answer 2

[Bùi Minh Quang]

a) $\frac{1}{8}+\frac{5}{8}=\frac{1+5}{8}=\frac{6}{8}=\frac{3}{4}$

b) $\frac{1}{15}+\frac{4}{15}=\frac{1+4}{15}=\frac{5}{15}=\frac{1}{3}$

c) $\frac{5}{9}+\frac{7}{9}=\frac{5+7}{9}=\frac{12}{9}=\frac{4}{3}$

d) $\frac{23}{100}+\frac{27}{100}=\frac{23+27}{100}=\frac{50}{100}=\frac{1}{2}$